t^2+4t+51=

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Solution for t^2+4t+51= equation:


Simplifying
t2 + 4t + 51 = 0

Reorder the terms:
51 + 4t + t2 = 0

Solving
51 + 4t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-51' to each side of the equation.
51 + 4t + -51 + t2 = 0 + -51

Reorder the terms:
51 + -51 + 4t + t2 = 0 + -51

Combine like terms: 51 + -51 = 0
0 + 4t + t2 = 0 + -51
4t + t2 = 0 + -51

Combine like terms: 0 + -51 = -51
4t + t2 = -51

The t term is 4t.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4t + 4 + t2 = -51 + 4

Reorder the terms:
4 + 4t + t2 = -51 + 4

Combine like terms: -51 + 4 = -47
4 + 4t + t2 = -47

Factor a perfect square on the left side:
(t + 2)(t + 2) = -47

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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